2024 day 3 part 2 solved

2024/3.py

@@ -2,12 +2,24 @@ import re
 
 lines = [l for l in open("input.txt", 'r').read().splitlines()]
 
-summa, x = 0, [] 
+summa, summa2, do = 0, 0, True
 
 for l in lines:
-    x = [i.span() for i in re.finditer("mul\([0-9]{1,3},[0-9]{1,3}\)", l)]
+    x = [i.span() for i in re.finditer(r"mul\([0-9]{1,3},[0-9]{1,3}\)", l)]
+    x2 = [i.span() for i in re.finditer(r"mul\([0-9]{1,3},[0-9]{1,3}\)|do\(\)|don't\(\)", l)]
+
     for start, end in x:
         tup = l[start:end].split(',')
         summa += int(tup[0][4:]) * int(tup[1][:-1])
 
-print(summa)
+    for start,end in x2:
+        if l[start:end] == 'do()':
+            do = True
+        elif l[start:end] == 'don\'t()':
+            do = False
+        elif do:
+            tup = l[start:end].split(',')
+            summa2 += int(tup[0][4:]) * int(tup[1][:-1])
+
+print(summa)
+print(summa2)